From 68c2a6ea1d909b0e37a641fe2f9831d5168fe34f Mon Sep 17 00:00:00 2001
From: Volker Mische <volker.mische@gmail.com>
Date: Fri, 19 Jan 2018 00:44:15 +0100
Subject: [PATCH] Hex strings no longer need have even number of digits

If a hex string has an odd number of bytes, the last byte is just
ignored in Node.js.
---
 index.js                       | 2 --
 test/node/test-buffer-alloc.js | 4 ++--
 2 files changed, 2 insertions(+), 4 deletions(-)

diff --git a/index.js b/index.js
index 6944c05..a6d094a 100644
--- a/index.js
+++ b/index.js
@@ -752,9 +752,7 @@ function hexWrite (buf, string, offset, length) {
     }
   }
 
-  // must be an even number of digits
   var strLen = string.length
-  if (strLen % 2 !== 0) throw new TypeError('Invalid hex string')
 
   if (length > strLen / 2) {
     length = strLen / 2
diff --git a/test/node/test-buffer-alloc.js b/test/node/test-buffer-alloc.js
index c813a23..dd4799c 100644
--- a/test/node/test-buffer-alloc.js
+++ b/test/node/test-buffer-alloc.js
@@ -516,13 +516,13 @@ assert.deepStrictEqual(Buffer.from(' YWJvcnVtLg', 'base64'),
     assert.strictEqual(hexb2[i], hexb[i]);
   }
 }
-/*
+
 // Test single hex character is discarded.
 assert.strictEqual(Buffer.from('A', 'hex').length, 0);
 
 // Test that if a trailing character is discarded, rest of string is processed.
 assert.deepStrictEqual(Buffer.from('Abx', 'hex'), Buffer.from('Ab', 'hex'));
-*/
+
 // Test single base64 char encodes as 0.
 assert.strictEqual(Buffer.from('A', 'base64').length, 0);
 
-- 
2.34.1